The synchronous speed of a four pole, 60 Hz single phase motor is what speed?

To determine the synchronous speed of a motor, the formula used is:

[ \text{Synchronous Speed (RPM)} = \frac{120 \times \text{Frequency (Hz)}}{\text{Number of Poles}} ]

In this case, the motor is a four-pole motor operating at a frequency of 60 Hz. Plugging these values into the formula yields:

[ \text{Synchronous Speed} = \frac{120 \times 60}{4} ]

This simplifies to:

[ \text{Synchronous Speed} = \frac{7200}{4} = 1800 , \text{RPM} ]

Therefore, the synchronous speed for a four-pole, 60 Hz motor is indeed 1800 RPM. This speed represents the theoretical maximum speed at which the magnetic field rotates in the motor, and it is essential for understanding how AC induction motors operate.

The other potential speeds—1200 RPM, 2100 RPM, and 3600 RPM—result from incorrect applications of the formula or different pole configurations and frequencies that do not apply to a four-pole motor at 60 Hz. The correct application of the synchronous speed formula confirms that 1800 RPM is accurate